Integrand size = 15, antiderivative size = 44 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {\sqrt {-a+b x}}{a x}+\frac {b \arctan \left (\frac {\sqrt {-a+b x}}{\sqrt {a}}\right )}{a^{3/2}} \]
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Time = 0.01 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {44, 65, 211} \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {b \arctan \left (\frac {\sqrt {b x-a}}{\sqrt {a}}\right )}{a^{3/2}}+\frac {\sqrt {b x-a}}{a x} \]
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Rule 44
Rule 65
Rule 211
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {-a+b x}}{a x}+\frac {b \int \frac {1}{x \sqrt {-a+b x}} \, dx}{2 a} \\ & = \frac {\sqrt {-a+b x}}{a x}+\frac {\text {Subst}\left (\int \frac {1}{\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {-a+b x}\right )}{a} \\ & = \frac {\sqrt {-a+b x}}{a x}+\frac {b \tan ^{-1}\left (\frac {\sqrt {-a+b x}}{\sqrt {a}}\right )}{a^{3/2}} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {\sqrt {-a+b x}}{a x}+\frac {b \arctan \left (\frac {\sqrt {-a+b x}}{\sqrt {a}}\right )}{a^{3/2}} \]
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Time = 0.08 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.89
method | result | size |
pseudoelliptic | \(\frac {b \arctan \left (\frac {\sqrt {b x -a}}{\sqrt {a}}\right ) x +\sqrt {b x -a}\, \sqrt {a}}{a^{\frac {3}{2}} x}\) | \(39\) |
derivativedivides | \(2 b \left (\frac {\sqrt {b x -a}}{2 a b x}+\frac {\arctan \left (\frac {\sqrt {b x -a}}{\sqrt {a}}\right )}{2 a^{\frac {3}{2}}}\right )\) | \(44\) |
default | \(2 b \left (\frac {\sqrt {b x -a}}{2 a b x}+\frac {\arctan \left (\frac {\sqrt {b x -a}}{\sqrt {a}}\right )}{2 a^{\frac {3}{2}}}\right )\) | \(44\) |
risch | \(-\frac {-b x +a}{a x \sqrt {b x -a}}+\frac {b \arctan \left (\frac {\sqrt {b x -a}}{\sqrt {a}}\right )}{a^{\frac {3}{2}}}\) | \(44\) |
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none
Time = 0.23 (sec) , antiderivative size = 97, normalized size of antiderivative = 2.20 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\left [-\frac {\sqrt {-a} b x \log \left (\frac {b x - 2 \, \sqrt {b x - a} \sqrt {-a} - 2 \, a}{x}\right ) - 2 \, \sqrt {b x - a} a}{2 \, a^{2} x}, \frac {\sqrt {a} b x \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right ) + \sqrt {b x - a} a}{a^{2} x}\right ] \]
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Result contains complex when optimal does not.
Time = 1.61 (sec) , antiderivative size = 121, normalized size of antiderivative = 2.75 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\begin {cases} \frac {i \sqrt {b} \sqrt {\frac {a}{b x} - 1}}{a \sqrt {x}} + \frac {i b \operatorname {acosh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{a^{\frac {3}{2}}} & \text {for}\: \left |{\frac {a}{b x}}\right | > 1 \\- \frac {1}{\sqrt {b} x^{\frac {3}{2}} \sqrt {- \frac {a}{b x} + 1}} + \frac {\sqrt {b}}{a \sqrt {x} \sqrt {- \frac {a}{b x} + 1}} - \frac {b \operatorname {asin}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{a^{\frac {3}{2}}} & \text {otherwise} \end {cases} \]
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none
Time = 0.31 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.05 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {\sqrt {b x - a} b}{{\left (b x - a\right )} a + a^{2}} + \frac {b \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right )}{a^{\frac {3}{2}}} \]
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none
Time = 0.32 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.98 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {\frac {b^{2} \arctan \left (\frac {\sqrt {b x - a}}{\sqrt {a}}\right )}{a^{\frac {3}{2}}} + \frac {\sqrt {b x - a} b}{a x}}{b} \]
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Time = 0.05 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.82 \[ \int \frac {1}{x^2 \sqrt {-a+b x}} \, dx=\frac {\sqrt {b\,x-a}}{a\,x}+\frac {b\,\mathrm {atan}\left (\frac {\sqrt {b\,x-a}}{\sqrt {a}}\right )}{a^{3/2}} \]
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